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***mysql中查询今天、昨天、上个月sql语句

king 安全防护 1970-01-01 813浏览 0
今天 select * from 表名 where to_days(时间字段名) = to_days(now());
昨天Select * FROM 表名 Where TO_DAYS( NOW( ) ) - TO_DAYS( 时间字段名) <= 1
7天Select * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 7 DAY) <= date(时间字段名)
近30天Select * FROM 表名 where DATE_SUB(CURDATE(), INTERVAL 30 DAY) <= date(时间字段名)
本月Select * FROM 表名 Where DATE_FORMAT( 时间字段名, '%Y%m' ) = DATE_FORMAT( CURDATE( ) , '%Y%m' )
上一月Select * FROM 表名 Where PERIOD_DIFF( date_format( now( ) , '%Y%m' ) , date_format( 时间字段名, '%Y%m' ) ) =1
#查询本季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(now());
#查询上季度数据
select * from `ht_invoice_information` where QUARTER(create_date)=QUARTER(DATE_SUB(now(),interval 1 QUARTER));
#查询本年数据
select * from `ht_invoice_information` where YEAR(create_date)=YEAR(NOW());
#查询上年数据
select * from `ht_invoice_information` where year(create_date)=year(date_sub(now(),interval 1 year));
 
查询当前这周的数据 
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now());
查询上周的数据
SELECT name,submittime FROM enterprise WHERE YEARWEEK(date_format(submittime,'%Y-%m-%d')) = YEARWEEK(now())-1;
查询当前月份的数据
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(now(),'%Y-%m')
查询距离当前现在6个月的数据
select name,submittime from enterprise where submittime between date_sub(now(),interval 6 month) and now();
查询上个月的数据
select name,submittime from enterprise   where date_format(submittime,'%Y-%m')=date_format(DATE_SUB(curdate(), INTERVAL 1 MONTH),'%Y-%m')
select * from ` user ` where DATE_FORMAT(pudate, ' %Y%m ' ) = DATE_FORMAT(CURDATE(), ' %Y%m ' ) ;
select * from user where WEEKOFYEAR(FROM_UNIXTIME(pudate,'%y-%m-%d')) = WEEKOFYEAR(now())
select * 
from user 
where MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select * 
from [ user ] 
where YEAR (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = YEAR (now())
and MONTH (FROM_UNIXTIME(pudate, ' %y-%m-%d ' )) = MONTH (now())
select * 
from [ user ] 
where pudate between 上月最后一天
and 下月第一天
where   date(regdate)   =   curdate();
select   *   from   test   where   year(regdate)=year(now())   and   month(regdate)=month(now())   and   day(regdate)=day(now())
SELECT date( c_instime ) ,curdate( )
FROM `t_score`
WHERE 1
LIMIT 0 , 30

  


原文链接地址:http://blog.knowsky.com/186111.htm

特别说明下:以下统计本周数据时,星期天是作为下周的第一天,而不是本周最后一天,因此你把星期天作为本周最后一天时,你需要在getDate()的基础上减一天,如dateadd('day', -1, getDate())
本周:select * from table where datediff(week,C_CALLTIME,getdate())=0 --C_CALLTIME 为日期字段

本月:select * from table where datediff(Month,C_CALLTIME,getdate())=0 --C_CALLTIME 为日期字段

本季:select * from table where datediff(qq,C_CALLTIME,getdate())=0

前半年1-6,后半年7-12:select * from table where datepart(mm,C_CALLTIME)/7 = datepart(mm,getdate())/7

昨天

select convert(varchar(10),getdate() - 1,120)

明天

select convert(varchar(10),getdate() + 1,120)

最近七天

select * from tb where 时间字段 >= convert(varchar(10),getdate() - 7,120)

随后七天

select * from tb where 时间字段 <= convert(varchar(10),getdate() + 7,120) and 时间字段 >= 时间字段

convert和dateadd函数结合使用就可以了。

用datediff(day,时间列,getdate())

上月

select * from tb where month(时间字段) = month(getdate()) - 1

本月

select * from tb where month(时间字段) = month(getdate())

下月

select * from tb where month(时间字段) = month(getdate()) + 1

--如果是在表中查詢

--昨天

Select * From TableName Where DateDiff(dd, DateTimCol, GetDate()) = 1

--明天

Select * From TableName Where DateDiff(dd, GetDate(), DateTimCol) = 1

--最近七天

Select * From TableName Where DateDiff(dd, DateTimCol, GetDate()) <= 7

--随后七天

Select * From TableName Where DateDiff(dd, GetDate(), DateTimCol) <= 7

--上周

Select * From TableName Where DateDiff(wk, DateTimCol, GetDate()) = 1

--本周

Select * From TableName Where DateDiff(wk, DateTimCol, GetDate()) = 0

--下周

Select * From TableName Where DateDiff(wk, GetDate(), DateTimCol ) = 1

--上月

Select * From TableName Where DateDiff(mm, DateTimCol, GetDate()) = 1

--本月

Select * From TableName Where DateDiff(mm, DateTimCol, GetDate()) = 0

--下月

Select * From TableName Where DateDiff(mm, GetDate(), DateTimCol ) = 1

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本周

sele

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